main() printf("%d\n",2*2+4*4+6*6);}#include<stdio.h>#define n 6 //这个是宏定义;如果是8,那么求的就是2*2+4*4+6*6+8*8。void main() int i; int s=0; for(i=2;i<=n;i+=2) s+=(i*i); } printf("%d\n",s);}这是原代码,希望对你有所帮助。。#include<stdio.h>int main() int sum; sum=2*2+4*4+6*6; printf("2*2+4*4+6*6=%d",sum); return 0;}#include
int main()
{
int i = 2, s = 0;
for (i = 2; i <= 100; i+=2){
s += i;
}
printf ("%d\n", s);
return 0;
}